ChappyNS
Senior Member
- Joined
- Oct 4, 2019
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- Location
- Halifax, NS (Canada)
- First name
- Mark
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I am currently playing a "Bridgehead" scenario and the allotment of VPs to the FRIENDLY side seems to make it extremely difficult to win.
First of all, the FRIENDLY side gets no casualty VPs unless they manage to eliminate a very rare AFV/gun activation for the ENEMY side. So almost always there will be no VPs awarded to the FRIENDLY side for this.
The only other way to get FRIENDLY VPs is to control activated fortification locations which can only be from S? that start on the river board. But here is the thing. The maximum S? that can be originally placed at start is 15 (which is the case in my mission). The ENEMY has an AC of 2. Statistically, that means that only 5 x S? will have a chance of activating. Out of those 5, and on Table A1, a DR of either "3", "4" or doubles (for this mission only) will produce an "F". This is very small. But to make it worse, you then have to roll on the fortification table, meaning you need a DR of "4" or less. I'm not a mathematician, but you don't need to be a rocket scientist to figure out that the chances of activating even one fortification is HIGHLY unlikely.
Note: if activated units on the river board dig entrenchments during the battle, this does not count for VP purposes. Only S? at the time of activation count.
And so, unless I am reading the rules incorrectly, this "Bridgehead" mission has a very high failure rate for the FRIENDLY side.
Thoughts anyone?
First of all, the FRIENDLY side gets no casualty VPs unless they manage to eliminate a very rare AFV/gun activation for the ENEMY side. So almost always there will be no VPs awarded to the FRIENDLY side for this.
The only other way to get FRIENDLY VPs is to control activated fortification locations which can only be from S? that start on the river board. But here is the thing. The maximum S? that can be originally placed at start is 15 (which is the case in my mission). The ENEMY has an AC of 2. Statistically, that means that only 5 x S? will have a chance of activating. Out of those 5, and on Table A1, a DR of either "3", "4" or doubles (for this mission only) will produce an "F". This is very small. But to make it worse, you then have to roll on the fortification table, meaning you need a DR of "4" or less. I'm not a mathematician, but you don't need to be a rocket scientist to figure out that the chances of activating even one fortification is HIGHLY unlikely.
Note: if activated units on the river board dig entrenchments during the battle, this does not count for VP purposes. Only S? at the time of activation count.
And so, unless I am reading the rules incorrectly, this "Bridgehead" mission has a very high failure rate for the FRIENDLY side.
Thoughts anyone?