- Thread starter Phlegm
- Start date

My knowledge of Special Relativity is mathematically rudimentary, but good enough for Government Work as they say, my knowledge of General Relativity is mathematically non existent, but I guess that for anyone familiar with GR math, such a calculation could be done during a short commuter bus ride home or even during a TV ad break.

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Now that you bring it up, for special relativity the Lagrange thingy equation 1/√(1-v²/c²) is the distortion (about my SR knowledge limit also). Let's see what speed would be required for the same effect. Let D(istortion) be the ratio of the rate ticking of the moving clock compared to that of the observer's clock, v the velocity and c the speed of light.

D = 1/√(1-v²/c²)

D = 1/(1-1.6*10^-9) = 1/√(1-v²/c²)

√(1-v²/c²) = 1-1.6*10^-9 = 0.9999999984

1-v²/c² = 0.99999999680000000256

v²/c² = 1 - 0.99999999680000000256 = 0.00000000319999999744

v/c = 5.6568542472296384949572544786157e-5

v ~ 16958.8 m/s or 37935.8 mph

The escape velocity from earth is ~ 11186 m/s and v is about 1.52 times that (~

So that figure of 30 months sees very, very plausible to me.

Earth's age ~ 4 billion years = 4*10^9 Y / 2.5 Y (IE 30 months) = 1.6*10^9 times the 30 month period.

Now that you bring it up, for special relativity the Lagrange thingy equation 1/√(1-v²/c²) is the distortion (about my SR knowledge limit also). Let's see what speed would be required for the same effect. Let D(istortion) be the ratio of the rate ticking of the moving clock compared to that of the observer's clock, v the velocity and c the speed of light.

D = 1/√(1-v²/c²)

D = 1/(1-1.6*10^-9) = 1/√(1-v²/c²)

√(1-v²/c²) = 1-1.6*10^-9 = 0.9999999984

1-v²/c² = 0.99999999680000000256

v²/c² = 1 - 0.99999999680000000256 = 0.00000000319999999744

v/c = 5.6568542472296384949572544786157e-5

v ~ 16958.8 m/s or 37935.8 mph

The escape velocity from earth is ~ 11186 m/s and v is about 1.52 times that (~**π**/2 ?)

So that figure of 30 months sees very, very plausible to me.

Now that you bring it up, for special relativity the Lagrange thingy equation 1/√(1-v²/c²) is the distortion (about my SR knowledge limit also). Let's see what speed would be required for the same effect. Let D(istortion) be the ratio of the rate ticking of the moving clock compared to that of the observer's clock, v the velocity and c the speed of light.

D = 1/√(1-v²/c²)

D = 1/(1-1.6*10^-9) = 1/√(1-v²/c²)

√(1-v²/c²) = 1-1.6*10^-9 = 0.9999999984

1-v²/c² = 0.99999999680000000256

v²/c² = 1 - 0.99999999680000000256 = 0.00000000319999999744

v/c = 5.6568542472296384949572544786157e-5

v ~ 16958.8 m/s or 37935.8 mph

The escape velocity from earth is ~ 11186 m/s and v is about 1.52 times that (~

So that figure of 30 months sees very, very plausible to me.

Earth's age ~ 4 billion years = 4*10^9 Y / 2.5 Y (IE 30 months) = 1.6*10^9 times the 30 month period.

The escape velocity from earth is ~ 11186 m/s and v is about 1.52 times that (~ **π**/2 ?)

So that figure of 30 months sees very, very plausible to me.

So that figure of 30 months sees very, very plausible to me.

I would hope that escape velocity is much, much higher, otherwise everything at the equator would drift/fly off into space, including air!

Don't forget that escape velocity is not only enough to get you into orbit beyond the atmosphere, but if earth was the only body in a static universe, it would allow you to disappear to infinity.

I have no more idea than you of how much mass distorts space or time, but I had a hunch that the 30 month mass induced difference would be of the same order of magnitude, at least, as escape velocity induced difference, turning out closer (1.52 x) than I expected.

One effect is that the adjustments necessary to make GPS accurate require allowance for both earth mass and orbital velocity, the mass speeding up the satellite's clock and the velocity slowing the satellite's clock, the velocity element being the larger effect. (compared to an earth based clock)

I would hope that escape velocity is much, much higher, otherwise everything at the equator would drift/fly off into space, including air!

Don't forget that escape velocity is not only enough to get you into orbit beyond the atmosphere, but if earth was the only body in a static universe, it would allow you to disappear to infinity.

I have no more idea than you of how much mass distorts space or time, but I had a hunch that the 30 month mass induced difference would be of the same order of magnitude, at least, as escape velocity induced difference, turning out closer (1.52 x) than I expected.

One effect is that the adjustments necessary to make GPS accurate require allowance for both earth mass and orbital velocity, the mass speeding up the satellite's clock and the velocity slowing the satellite's clock, the velocity element being the larger effect. (compared to an earth based clock)

D = 1/√(1-v²/c²)

D = 1/(1-1.6*10^-9) = 1/√(1-v²/c²)

√(1-v²/c²) = 1-1.6*10^-9 = 0.9999999984

1-v²/c² = 0.99999999680000000256

v²/c² = 1 - 0.99999999680000000256 = 0.00000000319999999744

v/c = 5.6568542472296384949572544786157e-5

v ~ 16958.8 m/s or 37935.8 mph

The escape velocity from earth is ~ 11186 m/s and v is about 1.52 times that (~**π**/2 ?)

So that figure of 30 months sees very, very plausible to me.

D = 1/(1-1.6*10^-9) = 1/√(1-v²/c²)

√(1-v²/c²) = 1-1.6*10^-9 = 0.9999999984

1-v²/c² = 0.99999999680000000256

v²/c² = 1 - 0.99999999680000000256 = 0.00000000319999999744

v/c = 5.6568542472296384949572544786157e-5

v ~ 16958.8 m/s or 37935.8 mph

The escape velocity from earth is ~ 11186 m/s and v is about 1.52 times that (~

So that figure of 30 months sees very, very plausible to me.

von Marwitz