sniper question

drklrd

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Just want tomake sure Ihave this right

a sniper attackis called for a dr is made and on a 1 or 2 the sniper rolls for his new hex 3 thru 6 nothing happens (if 10r 2 then 1 dice determines direction the other how far he moves for his attack hex) if there are targets in the hex he attacks there, if not he moves to the nearest hex with targets. If 3 possible targets were in his new hex random selection is rolled to see which one his attack is made against once one is selected the resolution is applied occording to whether it was a 1 or 2 from the first dr

now this is the part I am unclear about after all of this is done is a dr made for each other target in the hex to see if they are attacted also (so if 1 or 2 is the dr he moves attacks at least 1 target in the new hex but if he is lucky he could attack them all?
 

Brian W

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drklrd said:
now this is the part I am unclear about after all of this is done is a dr made for each other target in the hex to see if they are attacted also (so if 1 or 2 is the dr he moves attacks at least 1 target in the new hex but if he is lucky he could attack them all?
If, when selecting a target in a stack of eligible targets, random selection (RS) picks more than one target, then the player with the sniper picks from the group selected by RS. After applying the result to that one target, all other targets that were selected by RS have one dr each, and the result of that dr is applied as if they were the only targets of that dr.

EX: A (dr2) sniper lands in a hex with a 436, a 467 and a 9-1. RS is rolled and the result is:
436: dr2
467: dr4
9-1: dr4
The player with the sniper choses the 9-1 to suffer the dr2 result, wounding it. He could have choosen the 467, but would rather wound the leader than pin the 467. The 467 is now possibly attacked as well--the sniper player rolls die and the result is applied to that 467 as if it were the only target in the hex.
 
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