esprcorn
Member
Ok, caveat, I'm following up a facebook query that I'm not convinced of the consensus so I'm asking again here where I can elaborate my reasoning.
14.21 ALTERNATE TARGET: If the present target hex contains neither an eligible target (14.22) nor the enemy Sniper counter, the attacking Sniper counter is moved to, and will attack, the hex closest (in hexes) to that target hex which does contain one/both of them. Should ≥ two such hexes be equidistant, the Location with the lowest TEM is the target. Only the lowest (to a minimum of zero) in-hex TEM/SMOKE DRM applicable to any eligible target currently occupying that hex, regardless of LOS, is considered in the comparison [EXC: the +1 HA TEM, and the +1 Factory (but not that building) TEM, are NA]. Hidden Fortifications (e.g., entrenchments, Fortified Building Locations) may be revealed at this time. If the target hex is still undetermined, the Sniper player chooses which of those equidistant hexes to attack.
1) Sentence two establishes that between two equidistant hexes, choose the one with lowest TEM. This we all get...
2) Sentence 3 is where my debate begins. This states that when evaluating the in-hex TEM of each equidistant hex, use the lowest in-hex TEM or SMOKE DRM in each hex. So what does this mean? How many hexes have more than one in hex TEM? Basically only those with a printed terrain type AND smoke or WP. So this is stating that when considering a hex that has been SMOKED, use the lower of the two TEM's... Usually, this would NOT be the SMOKE.
Ok, what most people seem to think is that Sentence 3 is just reinforcing sentence 2 and saying the smoke counts. I disagree. If that were the case, sentence two would just say including smoke. I am a little uncertain about what (to a minimum of zero) might be referring to - how would you get less than zero?
As an example we have two equidistant hexes, both woods, one which has been SMOKED. If only sentence two I would say the woods only hex is the target. However sentence three says to use the lowest in-hex TEM for each - meaning count both as a woods hex - making them equivalent and giving the player the option to choose between the hexes.
14.21 ALTERNATE TARGET: If the present target hex contains neither an eligible target (14.22) nor the enemy Sniper counter, the attacking Sniper counter is moved to, and will attack, the hex closest (in hexes) to that target hex which does contain one/both of them. Should ≥ two such hexes be equidistant, the Location with the lowest TEM is the target. Only the lowest (to a minimum of zero) in-hex TEM/SMOKE DRM applicable to any eligible target currently occupying that hex, regardless of LOS, is considered in the comparison [EXC: the +1 HA TEM, and the +1 Factory (but not that building) TEM, are NA]. Hidden Fortifications (e.g., entrenchments, Fortified Building Locations) may be revealed at this time. If the target hex is still undetermined, the Sniper player chooses which of those equidistant hexes to attack.
1) Sentence two establishes that between two equidistant hexes, choose the one with lowest TEM. This we all get...
2) Sentence 3 is where my debate begins. This states that when evaluating the in-hex TEM of each equidistant hex, use the lowest in-hex TEM or SMOKE DRM in each hex. So what does this mean? How many hexes have more than one in hex TEM? Basically only those with a printed terrain type AND smoke or WP. So this is stating that when considering a hex that has been SMOKED, use the lower of the two TEM's... Usually, this would NOT be the SMOKE.
Ok, what most people seem to think is that Sentence 3 is just reinforcing sentence 2 and saying the smoke counts. I disagree. If that were the case, sentence two would just say including smoke. I am a little uncertain about what (to a minimum of zero) might be referring to - how would you get less than zero?
As an example we have two equidistant hexes, both woods, one which has been SMOKED. If only sentence two I would say the woods only hex is the target. However sentence three says to use the lowest in-hex TEM for each - meaning count both as a woods hex - making them equivalent and giving the player the option to choose between the hexes.