B is your answer as using A towards either hex AA1 or BB1 will be 4MF (A10.51 ...a routing unit must move to the nearest (in MF calculated at the start of its RtPh) building or woods hex... ) and is greater than the expenditure to hex BB1 thru BB2 (3MF); and C is out because it is not closer to a building/woods than B even though it would result in no possible interdiction could it rout there without using Low Crawl.View attachment 7683
the broken squad wants to low crawl. in to which of the three hexes A,B and C the unit may Low Crawl.
Additionaly Question: why A is not excluded because of it is not the shortest path to the rout target?
For some reason the player wanted to low crawl and didn't want to end up in the open. Don't know why. Perhaps it would mess up units moving along the road. A broken unit can always reach its rout target; its rout target has to be reachable for it to be a rout target. Low crawl is an option that is usually taken to avoid interdiction, but one can do it for any reason or no reason.Maybe I don't understand the question. BB1 is the rout target, but I thought once you determined the target you could take whatever rout path you wanted as long as you reach the target in that RtPh. So, there would be no need to low crawl because you could go through AA2 to BB1 in 4MF and you've satisfied all conditions. Is that not right?
Per A10.51 "...as long as it follows the shortest path in MF otherwise, it may enter a shellhole/entrenchment/pillbox to avoid Interdiction even if it can no longer reach that woods/building hex in a single RtPh. " No mention of being able to use SMOKE as cover for an additional MF expenditure, in fact it is specifically denied as it would then NOT be the shortest path in MF, thus A is out. The hex B is the only path that is the shortest in MF for meeting both the nearest in MF calculated at the start of the MPh to BB1 and being the shortest path in MF as noted herein.Maybe I don't understand the question. BB1 is the rout target, but I thought once you determined the target you could take whatever rout path you wanted as long as you reach the target in that RtPh. So, there would be no need to low crawl because you could go through AA2 to BB1 in 4MF and you've satisfied all conditions. Is that not right?
Per A10.51, "As long as it reaches that hex during a single RtPh, it need not use the shortest route, but as long as it folllows the shortest path in MF otherwise, it may enter a shellhole/entrenchment/pillbox to avoid Interdiction even if it can no longer reach that woods/building hex in a single RtPh." If it wants to use shellholes, etc which add MF, it must follow the otherwise-shortest route. If it doesn't want to use shellholes, etc, it need not use the otherwise-shortest route. In this case there were no shellholes, etc., so it need not use the otherwise-shortest route, and per a later sentence in A10.51 the broken unit need not reach that rout target.Per A10.51 "...as long as it follows the shortest path in MF otherwise, it may enter a shellhole/entrenchment/pillbox to avoid Interdiction even if it can no longer reach that woods/building hex in a single RtPh. " No mention of being able to use SMOKE as cover for an additional MF expenditure, in fact it is specifically denied as it would then NOT be the shortest path in MF, thus A is out. The hex B is the only path that is the shortest in MF for meeting both the nearest in MF calculated at the start of the MPh to BB1 and being the shortest path in MF as noted herein.
Therefore either AA2 or BB2 are the only legal hexes the unit may low crawl to (on the way to BB1).As the routing unit has chosen to low crawl
thanks for answer. I think you are right.B is your answer as using A towards either hex AA1 or BB1 will be 4MF (A10.51 ...a routing unit must move to the nearest (in MF calculated at the start of its RtPh) building or woods hex... ) and is greater than the expenditure to hex BB1 thru BB2 (3MF); and C is out because it is not closer to a building/woods than B even though it would result in no possible interdiction could it rout there without using Low Crawl.
My take (only MHO) is that the target hex must still be determined as per the statement of determining a rout destination at the Start of the RtPh (I believe almost everyone agrees with this position) and therefore BB1 must be the initial rout destination target. Again following the direction in A10.51 one must follow the path of least MF expenditure [EXC: the ability to enter Shellholes, Foxholes, etc.] even though that may not be the shortest route to the target hex (i.e. straight line hex distance). The EXC noted for Low Crawl does not relieve you from these parameters but simply says relieves you from the stipulation that one needs to attempt to reach the target destination hex that RtPh because you are only routing a single hex. Some believe that would allow you to chose A in the example provided but I do not believe so as this violates the shortest path in MF stipulation that you have not been relieved from; therefore only B is an acceptable answer. JMHO of course.thanks for answer. I think you are right.
I asked this question in the two facebook groups, and also cited your answer
However, so far all agree B is a possible hex.
some like AB only
some want ABC.
and some people see B as the only option.
with most players in the AB group
and continuously assuming you are right with B only.
for what is the "[EXC: if using Low Crawl] " good for ?
in 10.52 ”At the start of its RtPh, a routing unit must designate its destination and must attempt to reach it during that RtPh [EXC: if using Low Crawl].”
I disagree with this only in so far as because LC is a use of ALL MF to move one hex. The MF cost is immaterial.My take (only MHO) is that the target hex must still be determined as per the statement of determining a rout destination at the Start of the RtPh (I believe almost everyone agrees with this position) and therefore BB1 must be the initial rout destination target. Again following the direction in A10.51 one must follow the path of least MF expenditure [EXC: the ability to enter Shellholes, Foxholes, etc.] even though that may not be the shortest route to the target hex (i.e. straight line hex distance). The EXC noted for Low Crawl does not relieve you from these parameters but simply says relieves you from the stipulation that one needs to attempt to reach the target destination hex that RtPh because you are only routing a single hex. Some believe that would allow you to chose A in the example provided but I do not believe so as this violates the shortest path in MF stipulation that you have not been relieved from; therefore only B is an acceptable answer. JMHO of course.
how do you explain the:I disagree with this only in so far as because LC is a use of ALL MF to move one hex. The MF cost is immaterial.
beacuse the nearest woods/building location within 6MF is how you determine the initial rout destination hex.how do you explain the:
"All other Rout provisions apply unchanged to Low Crawl, e.g., rout must still be towards the nearest
woods/building Location within 6 MF"
in 10.52 when MF is immaterial ?
I agree with the A or B but...where in the rules does it say LC uses ALL MF?beacuse the nearest woods/building location within 6MF is how you determine the initial rout destination hex.
As has been explained previously numerous times, the first thing you do in the rout phase for a routing unit is determine the destination hex. That is what that phrase is referring to. A low crawl uses ALL MF of the routing unit, therefore whether it costs 2, 3 4 or 5 MF is not relevant, it is a ONE HEX move. But it must be towards that initial rout destination hex as determined in step 1.
A10.52:I agree with the A or B but...where in the rules does it say LC uses ALL MF?