Improbable hit AND possible CH: one or two subsequent dr?

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Situation: in a Location, one concealed unit and one unconcealed unit. Opponent tank fires and get a TH DR of 2, which is just what was needed to hit the unconcealed unit and is also an improbable hit on the concealed unit.
Question: is it necessary to do 2 different subsequent dr or just one?
If one dr for each case:
  • for the unconcealed unit => dr1 = CH, dr2-6 = Normal hit
  • for the concealed unit => dr1 = CH, dr2-3 = Normal hit, dr4-6 no hit
If just one dr for both cases => dr1 = CH with Random selection, dr2-3 = both units are hit, dr4-6 unconcealed unit hit
 

bendizoid

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Situation: in a Location, one concealed unit and one unconcealed unit. Opponent tank fires and get a TH DR of 2, which is just what was needed to hit the unconcealed unit and is also an improbable hit on the concealed unit.
Question: is it necessary to do 2 different subsequent dr or just one?
If one dr for each case:
  • for the unconcealed unit => dr1 = CH, dr2-6 = Normal hit
  • for the concealed unit => dr1 = CH, dr2-3 = Normal hit, dr4-6 no hit
If just one dr for both cases => dr1 = CH with Random selection, dr2-3 = both units are hit, dr4-6 unconcealed unit hit
Two dr
 

EagleIV

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I would think there would be 1 dr with the results as you said and I don't see any Q&A
 

STAVKA

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Situation: in a Location, one concealed unit and one unconcealed unit. Opponent tank fires and get a TH DR of 2, which is just what was needed to hit the unconcealed unit and is also an improbable hit on the concealed unit.
Question: is it necessary to do 2 different subsequent dr or just one?
If one dr for each case:
  • for the unconcealed unit => dr1 = CH, dr2-6 = Normal hit
  • for the concealed unit => dr1 = CH, dr2-3 = Normal hit, dr4-6 no hit
If just one dr for both cases => dr1 = CH with Random selection, dr2-3 = both units are hit, dr4-6 unconcealed unit hit
One dr
 
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