I think this is a simple one, but need some clarification;
When a K/# result is obtained on the IFT, is the casualty reduction HS placed on the board in a "broken" state? As well, I'm assuming that it needs to undergo the required MC (for instance, a good order mmc would be reduced to a "broken" HS, then need to undergo a +4 MC if the result was K/4)?
Who determines which units in a hex are used to satifiy a K or KIA result? ASLSK explains this as "randomly determined"?
Thanks for the help,
Jesse
When a K/# result is obtained on the IFT, is the casualty reduction HS placed on the board in a "broken" state? As well, I'm assuming that it needs to undergo the required MC (for instance, a good order mmc would be reduced to a "broken" HS, then need to undergo a +4 MC if the result was K/4)?
Who determines which units in a hex are used to satifiy a K or KIA result? ASLSK explains this as "randomly determined"?
Thanks for the help,
Jesse