E2.3 LOS/Range Restriction for Interrogation (E2)

[Mr Incredible]

Just one question about E2.3:

"No unit/Fortification is revealed if it is both out of LOS of the Prisoner and more than eight hexes away".

Now I always took that to mean the HIP/? had to be both within 8 hexes and LOS. But re-reading that my opponent and I came up with that it meant:

• If within 8 hexes and out of LOS it was revealed
• If beyond 8 hexes but in LOS it was revealed

Both situation for closest HIP/? only.

Is that reading correct?

 

[Robin Reeve]

"both out of LOS of the Prisoner and more than eight hexes away" :

• both means the two conditions must be met.
• and confirms the necessity to meet the two conditions

 

[Mr Incredible]

Would have been easier to understand in the positive inclusive, not a negative exclusive.

Revealed if either in LOS at any distance or out of LOS but within 8 hexes.

 

[Stewart]

Just one question about E2.3:

"No unit/Fortification is revealed if it is both out of LOS of the Prisoner and more than eight hexes away".

Now I always took that to mean the HIP/? had to be both within 8 hexes and LOS. But re-reading that my opponent and I came up with that it meant:

• If within 8 hexes and out of LOS it was revealed
• If beyond 8 hexes but in LOS it was revealed

Both situation for closest HIP/? only.

Is that reading correct?

You Left out
Its LOS that it can reach in ITS next Mph. so its MPH +8hexes

 

[ScottRomanowski]

Use De Morgan's Laws:
"No unit/Fortification is revealed if it is both out of LOS of the Prisoner and more than eight hexes away".
Not revealed = (out of LOS) AND (> 8 hexes away)
negate both sides
not( Not revealed) = Revealed = not( (out of LOS) AND (> 8 hexes away))
= not(out of LOS) OR not(> 8 hexes away)
= (in LOS) OR (<= 8 hexes away)

"A unit/Fortification is revealed if it is either in LOS of the Prisoner, or eight or fewer hexes away".

BTW, we could have avoided all the "or" vs "and/or" confusion by rephrasing everything in terms of only NAND or NOR.

 

[Sparafucil3]

BTW, we could have avoided all the "or" vs "and/or" confusion by rephrasing everything in terms of only NAND or NOR.

Logic? In an ASL forum? Sorry, we're here to pick and nits and get morally outraged by them. -- jim

 

[Stewart]

Use De Morgan's Laws:
"No unit/Fortification is revealed if it is both out of LOS of the Prisoner and more than eight hexes away".
Not revealed = (out of LOS) AND (> 8 hexes away)
negate both sides
not( Not revealed) = Revealed = not( (out of LOS) AND (> 8 hexes away))
= not(out of LOS) OR not(> 8 hexes away)
= (in LOS) OR (<= 8 hexes away)

"A unit/Fortification is revealed if it is either in LOS of the Prisoner, or eight or fewer hexes away".

BTW, we could have avoided all the "or" vs "and/or" confusion by rephrasing everything in terms of only NAND or NOR.

Right, but the Unit can't move OUT of his hex...BUT if was on the bottom level of a 3rd level building is "allowed" to move up to LEVEL 3 to reveal, as that location is still within its own hex.
AND that if there were no stairwell but a stairwell ADJ. Then the unit may "move" up the adjacent stairwell to reenter its previous HEX to get up a higher level in its starting position.

Correct?

 

[Sparafucil3]

Right, but the Unit can't move OUT of his hex...BUT if was on the bottom level of a 3rd level building is "allowed" to move up to LEVEL 3 to reveal, as that location is still within its own hex.
AND that if there were no stairwell but a stairwell ADJ. Then the unit may "move" up the adjacent stairwell to reenter its previous HEX to get up a higher level in its starting position.

Correct?

Assuming it had the movement factors to get to the upper Level Location in a theoretical MPh, you are correct. If as in your example, the unit was a Squad/HS using a stairwell in an Adjacent Location to get to a Level 3, it could get from Level 1 to Level 3 if it were to CX. Of course, this assumes the Stairwell is ADJACENT. -- jim

 

[ScottRomanowski]

I think Sparafucil3 and Stewart have it right. I think the "could conceivably reach in its next MPh" includes moving out of its current hex to use a stairwell. So a non-CX non-inexperienced MMC captured in 1G4h0 could conceivably DT in its hypothetical next MPh to G3 - G3h1 - G3h2 - G4h2 (6MF). One captured in 1E4h0 can't reach an upper level location of E4 so it's limited to LOS from ground level of E4.