WuWei
Elder Member
Just checking if we played this right.
Somewhere in Stalingrad:
A concealed, stealthy Russian 447 advanced into a Factory hex with a concealed German 8-1 and a (unconcealed) broken 547.
There's an Ambush roll. The Russians get -2 (concealment) and -1 (stealthy) so -3. The Germans get -1 (leader bonus), -2 (concealment) and +1 (broken unit), for a total of -2.
Hypothetical: If the Germans got Ambush, the 8-1 and/or the broken 547 could move out of the hex into an accessible location.
Reality: There's no Ambush. The Germans decline to attack, so the 8-1 stays concealed. The Russian attack is halved, so it's 2:6 -> 1:4, but they get -2 vs. broken unit. They declare H-to-H, for a Kill# of 5. They rolled an 11 for no effect.
Hypothetical:
A rolled 4 or lower would have eliminated both German units.
A rolled 5 would have CRed the squad or wounded the leader, random selection.
A rolled 6 would have eliminated the broken squad.
A rolled 7 would have CRed the broken squad.
Is that correct?
Somewhere in Stalingrad:
A concealed, stealthy Russian 447 advanced into a Factory hex with a concealed German 8-1 and a (unconcealed) broken 547.
There's an Ambush roll. The Russians get -2 (concealment) and -1 (stealthy) so -3. The Germans get -1 (leader bonus), -2 (concealment) and +1 (broken unit), for a total of -2.
Hypothetical: If the Germans got Ambush, the 8-1 and/or the broken 547 could move out of the hex into an accessible location.
Reality: There's no Ambush. The Germans decline to attack, so the 8-1 stays concealed. The Russian attack is halved, so it's 2:6 -> 1:4, but they get -2 vs. broken unit. They declare H-to-H, for a Kill# of 5. They rolled an 11 for no effect.
Hypothetical:
A rolled 4 or lower would have eliminated both German units.
A rolled 5 would have CRed the squad or wounded the leader, random selection.
A rolled 6 would have eliminated the broken squad.
A rolled 7 would have CRed the broken squad.
Is that correct?